Answer:
Assuming that there are two different fractions:
Probability of rolling a sum of 12 = \frac{1}{36}
36
1
Probability of rolling a sum of 11 = \frac{2}{36}
36
2
Explanation:
To find probability (p)
p(event)=\frac{number of favorable outcomes}{number of possible outcoumes}p(event)=
numberofpossibleoutcoumes
numberoffavorableoutcomes
All of the possible sums of 11 or 12:
For possible ways to make 11:
5,6 and 6,5
For possible ways to make 12:
6,6
All of the possible outcomes in total are 36
All of the possible outcomes to roll a sum of 11 are 2
All of the possible outcomes to roll a sum of 12 are 1
Form the fraction for each
p(of rolling a 12)= \frac{1}{36}p(ofrollinga12)=
36
1
p(of rolling an 11)= \frac{2}{36}p(ofrollingan11)=
36
2
Simplify if necessary and you are good to go!