Question

A pendulum of length 1m and period 2.01s is placed at the top of mount everest having an altitude of 8849m. calculate the value of g at that point

Answer 1

F = K M / R^2 acceleration due to gravity at R

F2 / F1 = (R1 / R2)^2

R1 = radius of earth = 6.37E6 m

R2 = 6.37E6 + 8.85E3 = 6.38E6

F2 / F1 = .9984^2 = .997

The value of g would only be about .003 less than at the surface