Question

A plane flies at a steady rate of 40 mph while a second plane flies at a steady rate of 100 mph. The planes are 200 miles apart and fly directly toward each other. In how many hours will they meet?

Answer 1

`1\ \text{hour}\ 25\ \text{minutes and }12\ \text{seconds}`

Explanation:

The combined distance that both planes will cover is 200 miles

Time taken by both planes will be the same (t)

`\text{Distance}=\text{Speed}* \text{Time}`

So, the combined distance is

`40t+100t=200\\\Rightarrow 140t=200\\\Rightarrow t=(200)/(140)\\\Rightarrow t=1.42\ \text{hours}=1\ \text{hour}\ 25\ \text{minutes and }12\ \text{seconds}`

They will meet in
`1\ \text{hour}\ 25\ \text{minutes and }12\ \text{seconds}`.

Answer 2

Answer: 10/7 hrs

Explanation:

Step 1 of 5:Let’s organize the given information. Fill in the Rate column :

Rate (mph) Time (h) Distance (mi)

1st plane 40

2nd plane 100

Step 2 of 5:Let x hours be the time it will take them to meet. Complete the chart using the formula : Distance= Rate x Time :

Rate (mph) Time (h) Distance (mi)

1st plane 40 x

2nd plane 100 x

Step 3 of 5:We know that the distance between the planes was 200 miles.

Use this to make an equation : 40x+100x=200

.

Step 4 of 5:Solve the equation : 10/7

Step 5 of 5:Read the problem and answer the question in the problem.

It will take them

hours. 10/7 hrs