Question

What is the energy of a photon of red light having a frequency of 3.08 x 10^14 HZ?​

Answer 1

2.97*10-19 j

Step-by-step explanation:

E=Energy of photon

H=Planck constant=6.626*10-34

V=Frequency of photon

we can plug what we already know E=(6.626*10-34)(4.48*10 14)

Answer 2

2.04 x 10⁻¹⁹J

Step-by-step explanation:

Given parameters:

Frequency = 3.08 x 10¹⁴Hz

Unknown:

The energy of the photon = ?

Solution:

The energy of a photon is given as;

E = hf

Where h is the planck's constant

f is the frequency

Insert the parameters and solve;

E = 6.63 x 10⁻³⁴ x 3.08 x 10¹⁴

E = 20.4 x 10⁻³⁴⁺¹⁴

E = 20.4 x 10⁻²⁰ = 2.04 x 10⁻¹⁹J