Question

–h2 – 4h + 5 = 0 solve quadratic equation

Answer 1

`x=-5, 1`

General Formulas and Concepts:

Order of Operations: BPEMDAS

Standard Form: ax² + bx + c = 0

Quadratic Formula:
`x=(-b\pm√(b^2-4ac) )/(2a)`

Explanation:

Step 1: Define

-h² - 4h + 5 = 0

a = -1

b = -4

c = 5

Step 2: Solve for x

1. Substitute:
   `x=(-(-4)\pm√((-4)^2-4(-1)(5)) )/(2(-1))`
2. Simplify:
   `x=(4\pm√((-4)^2-4(-1)(5)) )/(2(-1))`
3. Exponents:
   `x=(4\pm√(16-4(-1)(5)) )/(2(-1))`
4. Multiply:
   `x=(4\pm√(16+20) )/(-2)`
5. Add:
   `x=(4\pm√(36) )/(-2)`
6. Evaluate:
   `x=(4\pm6 )/(-2)`
7. Evaluate:
   `x=-5, 1`