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Find the equivalent resistance of this circuit. ​

Find the equivalent resistance of this circuit. ​-example-1
User Biomancer
by
8.7k points

2 Answers

6 votes

Answer:

320

Step-by-step explanation:

Group R1 and R2

Then group R1'2 with R3

Find the equivalent resistance of this circuit. ​-example-1
User Ecm
by
7.6k points
9 votes

Explaination :

Here the given circuit is both in series and parallel. So we would be first calculating the total resistance in series.

Rs = R1 + R2 .... n

Rs = 100Ω + 220Ω

Rs = 320Ω

Therefore, resistance in series combination is of 320Ω.

Now, the circuit would be combined in parallel.

As we know that,

  • 1/Rp = 1/R1 + 1/R2 +... 1/n

>> 1/Rp = 1/320 + 1/320

>> 1/Rp = 1 + 1 / 320

>> 1/Rp = 2 / 320

>> 1/Rp = 1 / 160

Cross multiplying them,

>> Rp = 160Ω

Therefore,

  • Equivalent resistance of circuit is of 160Ω

User Uday Sawant
by
8.5k points

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