Required answer:
![\huge{ \boxed{\bold{ \tt{45 = 2x}}}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/6vpg2j07q3mpulzqrfbygnu0iydyv2v83f.png)
Question:
Use cross products to identify the equation needed to solve this proportion:
5/x = 2/9
0 5x = 18
0 2x = 45
O 9x = 10
O 2x = 14
Equation Given:
5/x = 2/9
Step by step explanation:
![: \implies (5)/(x) = (2)/(9) </p><p></p><p>](https://img.qammunity.org/2021/formulas/mathematics/high-school/vzsakug5a5agsxd0kv58eokc29etc8fcwt.png)
equation formed
![: \implies \: 5 * 9 = 2 * x](https://img.qammunity.org/2021/formulas/mathematics/high-school/z2calk3ljl56sfrmsoayc3lfp5kaan9b4e.png)
we have taken 9 up to multiply it with 5 and x up to multiply it with2
![: \implies \: 45 = 2x](https://img.qammunity.org/2021/formulas/mathematics/high-school/y73nlhrk1aktnw9xzh2xox4egpbjezqwl3.png)
after multiplication we get 45 = 2x
extra steps:
![: \implies \: x=(45)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ud4rxcpiyi1hnqrgzjkpso51uhxb424a5d.png)
transferring 2 to other side to divide it with 45
![: \implies \: x=22.5](https://img.qammunity.org/2021/formulas/mathematics/high-school/bvzcqburm7msowo7zcxaz6s5e1pb5282ix.png)
so finally we get 22.5