Question

2 point

Question 9
An object is shot from the ground at 75m/s at an angle of 45° above the horizontal. How high does the object get before beginning its descent?

Answer 1

Before beginning its descent, the object gets 143.5 meters high

Step-by-step explanation:

Projectile Motion

It's known as the type of motion that experiences an object that is projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and
`g=9.8m/s^2` the acceleration of gravity, then the maximum height reached by the object is:

`\displaystyle y_m=(v_o^2\sin^2\theta)/(2g)`

The object is shot at vo=75 m/s at an angle of θ=45°. The maximum height is calculated below:

`\displaystyle y_m=(75^2\sin^2 45^\circ)/(2\cdot 9.8)`

`\displaystyle y_m=(5625\cdot 0.707^2)/(19.6)`

`y_m=143.5\ m`

Before beginning its descent, the object gets 143.5 meters high