We are given that, a computer can sort x objects in t seconds, and the below relations is satisfied for each x and t
For 12 objects, we can substitute x = 12
⇒ t = (3/1000) (12)² + (1/1000) 12
⇒ t = (12/1000) (3 × 12 + 1)
⇒ t = (12×37/1000)
⇒ t = 444/1000
⇒ t = 0.444
⇒ t ≈ 0.40 seconds (2 dp)