Question

A
32°
B
D
O
С
mZC =
[?]
Help please

Answer 1

58

Explanation:

This is a little tough to answer. It looks ambiguous. If BaD = 32 then <C is the compliment of BDC.

90 - 32 = 58 I think this is the intended answer.

However if 32 = ADC then <BDC = 16 (1/2 the entire angle at D)

Therefore <C = 90 - 16 = 74

In any event <ADB and <CDB are equal.