Answer:
a=4
Explanation:
Hi there!
We are looking for the value of
. We know that
and
.
We'll start with the Pythagorean theorem:

Now, we'll subtract
from both sides so that
is by itself.

We can now substitute our known values of
and
into the equation. Make sure to put the substituted values in parenthesis.

Let's apply the exponents to the values we substituted in:


Now, to eliminate the exponent on
, we take the square root of both sides:


Let me know if you have any questions!