Question

Can y’all help ? I need both

Answer 1

`part \: a. \: \\ ................................................. \\ \boxed{has \: no \: solution}. \\ \\ part \: b. \: \\ ................................................. \\ \boxed{has \: no \: solution}.`

Explanation:

`part \: a. \: \\ ................................................. \\ - 2(x - 3) - 4 \geqslant 3x - 5(x - 1) \\ - 2x + 3 - 4 \geqslant 3x - 5x + 5 \\ - 2x + 2x \geqslant 5 + 4 \\ 0 \geqslant 9 \\ 0 \: can \: not \: be \: equal \: or \: greater \: than \: 9. \\ hence \: the \: equation \: \boxed{has \: no \: solution}. \\ \\ part \: b. \: \\ ................................................. \\ 7x - 3(x - 1) = 2(2x + 3) \\ 7x - 3x + 3 = 4x + 6 \\ 4x - 4x = 6 - 3 \\ 0 = 3 \\ 0 \: can \: never \: be \: equal \: to \: 3 \\ hence \: the \: equation \: \boxed{has \: no \: solution}.`

♨Rage♨