Answer:
2. x=25°
3. x=15°
4. x=26°
Explanation:
For problem 2, we know the sum of the angles of a triangle is 180°. Also, supplementary angles are 180°.
30+20+x=180 [combine like terms]
50+x=180 [subtract both sides by 50]
x=130
Now that we have the missing angle, we can use that to solve for x.
2x+130=180 [subtract both sides by 130]
2x=50 [divide both sides by 2]
x=25°
Now, we know that x=25°.
For problem 3, we know the sum of the angles of a triangle is 180°. This means, we add all the angles together and get 180°.
8x+25+2x+5=180 [combine like terms]
10x+30=180 [subtract both sides by 30]
10x=150 [divide both sides by 10]
x=15°
Now, we know that x=15°.
For problem 4, we know the sum of the angles of a triangle is 180°. This means, we add all the angles together and get 180°.
x+12+52+90=180 [combine like terms]
x+154=180 [subtract both sides by 154]
x=26°
Now, we know that x=26°.