Question

If you throw a ball up with a velocity of 3 m/s , how long will it take for the ball to reach the top of its path

Answer 1

t = 0.306 s

Step-by-step explanation:

Given that,

Initial velocity of the ball, u = 3 m/s

When it reaches the top of its path, its final velocity, v = 0

We need to find the time it takes the ball to reach the top of its path. It can be calculated using first equation of motion.

v = u +at

Here, a = -g

`0=u-gt\\\\t=(u)/(g)\\\\t=(3\ m/s)/(9.8\ m/s^2)\\\\t=0.306\ s`

So, the ball will take 0.306 s to reach the top of its path.