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3 votes
Calculate the distance between the points (7, 4) and (-5, -3).​

2 Answers

6 votes

Answer:

D = √193 units

or

D = 13.892 units

Step-by-step explanation:

Given:

(7, 4) and (-5, -3)

Calculate the distance

Solution:


\rm \: Distance (D) = \sqrt{( x_(2) - x_(1)) {}^(2) + (y_(2) - y_{1) {}^(2) }}

Now, substitute the values given:


\rm \: D = \sqrt{ \{( - 5) - 7 \}^(2) + \{( - 3) - 4 {}^{} \} {}^(2) }


\rm \: D = \sqrt{ \{12 \}^(2) + \{( - 3) - 4 {}^{} \} {}^(2) }


\rm \: D = \sqrt{ 144 + \{( - 3) - 4 {}^{} \} {}^(2) }


\rm D = \sqrt{144 + \{ 7\}{}^(2) }


\rm \: D = √(144 + 49)


\boxed{\rm \: D = √(193)}


\boxed{\rm \: D =13 .892}

Thus, Distance between the two given points will be √193 or √13.892 units.

User Pergy
by
7.2k points
5 votes

Answer:


\bf √(193) units or 13.9 units is the distance.

Step-by-step explanation:


\sf Distance \ between \ two \ points = √((x_2 - x_1)^2 +(y_2 - y_1)^2)

Given points: (7, 4) and (-5, -3)

Identify following:


\sf x_2= 7,
\sf x_1 = -5,
\sf y_2 =4,
\sf y_1 =-3

Find distance:


\rightarrow \sf √((7 - (-5))^2 + (4 - (-3))^2) \quad = \quad √(144+49) \quad = \quad √(193) \quad \approx \ 13.9

User M A Salman
by
6.5k points