Question

Pre-Calc Question: Given sinx-2sinxcosx=0, how do you solve for x through factoring?

Answer 1

2sin(x)cos(x) = sin(x)

2sin(x)cos(x) - sin(x) = 0

sin(x)(2cos(x) - 1) = 0

sin(x) = 0

x = 0, pi, 2pi

2cos(x) - 1 = 0

cos(x) = 1/2

x = pi/3, 5π/pi

x = 0, pi/3, pi, 5 pi/3, 2 pi

hope it helps