Question

The coefficient of friction on a surface is 0.25. A box requires

100 N to slide it across the surface. What is the weight of the box?

Answer 1

Step-by-step explanation:

Let mass of box = m

weight = mg

limiting friction = μ mg , where μ is coefficient of friction

= .25 x m x 9.8 = 2.45 m

According to problem

2.45 m = 100

m = 40.816 kg

weight = 40.816 x 9.8 = 400 N .