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L 2. (a) Which term of the arithmetic progression 8 - 6i, 7 – 4i, 6 — 2i, ... is purely imaginary [3]​

1 Answer

7 votes

Answer:

10i

Explanation:

8-7=1

7-6=1

The real part of the complex numbers is following an arithmetic progression with first term 8 and common difference 1.

………………………………………

-6+2=-4

-4+2=-2

THe Imaginary part of the complex numbers is following an arithmetic progression with first term -6 and common difference 2.

………………………………………

Then the term she of the sequence can be written:

(8 - n) + i(-6 + 2n)

………………………………………

We get a purely imaginary term when its real part is nul :

⇒ 8 - n = 0

⇒ 8 = n

………………………………………

If we take n = 8

⇒ -6 + 2n = -6 + 2×8 = -6 + 16 = 10

Therefore,

The term of the arithmetic progression 8 - 6i, 7 – 4i, 6 — 2i, ... which is purely imaginary is :

10i

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