Question

In the diagram below, l || m and QR perpendicular ST at R.

If m<1 = 63. find m<2

Answer 1

m<2 = 27°

Explanation:

m<1 = 63° (given)

m<QTR = m<1 (alternate interior angles are congruent)

m<QTR = 63° (Substitution)

m<QRT = 90° (right angle)

m<2 + m<QRT + m<QTR = 180°

m<2 + 90° + 63° = 180° (substitution)

m<2 + 153° = 180°

Subtract 153° from each side

m<2 = 180° - 153°

m<2 = 27°