Question

Use the given values of n and p to find the minimum usual value μ- 20 and the maximum usual value μ+20. Round your answer to the nearest hundredth unless otherwise noted.

n=713, p= 4/5
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Answer 1

Min:549.04; Max:591.76

Explanation:

Answer 2

• μ - 2σ = 549.04
• μ + 2σ = 591.76

Explanation:

Given the parameters of binomial distribution

• n = 713, p = 4/5

We need to find the mean μ and the standard deviation σ to calculate required values

Follow the steps below

1. Find the mean

• μ = n·p = 713*(4/5) = 570.4

2. Find the variance

• σ² = np(1 - p) = 713*(4/5)*(1 - 4/5) = 114.08

3. Find the standard deviation

• σ = √114.08 = 10.68 (rounded)

Find the minimum usual value

• μ - 2σ = 570.4 - 2*10.68 = 549.04

Find the maximum usual value

• μ + 2σ = 570.4 + 2*10.68 = 591.76