Question

8. Follow-up When the ferry leaves Guemes Island and heads back

toward Anacortes, its speed increases from 0 to 5.8 m/s in 9.25 s. What
is its average acceleration?

Answer 1

0.63m/s²

Step-by-step explanation:

The average acceleration can be derived from using the formula:

V = u + at

Where v = final velocity (m/s)

u = initial velocity (m/s)

a = acceleration (m/s²)

t = time (s)

V = u + at

V - u = at

a = v - u/t

a = ∆V/t

According to the provided information; v = 5.8m/s, u = 0m/s, t = 9.25s

a = ∆V/t

a = (5.8-0)/9.25

a = 5.8/9.25

a = 0.627

a = 0.63m/s²

Hence, the average acceleration is 0.63m/s²

Answer 2

The average acceleration of the ferry which leaves Guemes Island and heads back toward Anacortes is 0.627m/s².

Given the data in the question;

• Initial speed;
  `u = 0`

• Final speed;
  `v = 5.8m/s`

• Time taken;
  `t = 9.25s`

To determine the average acceleration, we use the first equation of motion:

`v = u + at`

Where v is final speed, u is initial speed, a is acceleration and t is time taken.

We substitute our given values into the equation

`5.8m/s = 0 + [ a * 9.25s ]\\\\5.8m/s = a * 9.25s\\\\a = (5.8m/s)/(9.25s)\\\\a = 0.627m/s^2`

Therefore, the average acceleration of the ferry which leaves Guemes Island and heads back toward Anacortes is 0.627m/s².