Question

A chemist prepares a standard solution in the lab using a 500.0 mL volumetric flask. 4.865 g of NaCl is used. What is the molarity of the NaCl solution?

Answer 1

0.17 mol/l

Step-by-step explanation:

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⠀⠀⠀⠀▨ Note

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• What is molarity?

Molarity is the amount of moles of component present in certain volume of solution.

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• What is mole?

Mole is a unit in chemistry i.e. 6.022×10²³ ions, atoms or molecules present in the substance.

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⠀⠀⠀⠀● Solution

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Weight of NaCl(m) = 4.865 grams

Volume(V) = 500ml = 0.5 liters

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1 mole of NaCl = 58g

So 4.865g of NaCl(n)

`= \sf (4.865)/(58) = 0.084 \: moles`

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While

`\frak{molarity = (no \: of \: moles)/(volume) }`

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Substituting the required values

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`\sf \implies molarity = (n)/(V) \\ \\ \sf \implies molarity = (0.084)/(0.5) \\ \\ \ \boxed{ \tt{ \implies molarity = 0.17 \: mol \: {l}^( - 1) }}`