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It is given that x=3 is a root of the equation 4x^2 + kx- 15 = 0 , where k is a constant.Find

a) the value of k
b) the other root

2 Answers

5 votes

Above answer is also correct. Anyways check my attached picture answer.

Thanks !

It is given that x=3 is a root of the equation 4x^2 + kx- 15 = 0 , where k is a constant-example-1
User Bertvh
by
8.5k points
4 votes

Answer:

a) k = -7

b) x = -5/4

Explanation:


4x^2+kx-15=0

Substitute
x=3 and solve for
k:


4(3^2)+3k-15=0\\36+3k-15=0\\3k=-21\implies k=\boxed{-7}

Plugging
k back in to
4x^2+kx-15=0:


4x^2-7k-15=0

Factor:


(4x+5)(x-3)=0


4x+5=0\implies x=\boxed{-(5)/(4)}

User Muath
by
8.0k points

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