Question

1. find the distance between the points (-4,-6 ) and (8,5) to the nearest 100th of a unit. *

(3 Points)
16.26
16.32
16.28

Answer 1

Distance is 16.28.

Explanation:

`Distance=\sqrt{((5--6)^(2)+(8--4)^(2) } =\sqrt{11^(2)+12^(2) }=√(121+144) =√(265)=16.28`