Question

Question 1.) 3(2x + 4) = 2(2x - 2)

Question 2.) 4.3x - 6 = 8 + 2.3x

Question 3.) 6(x-8) = 8x -36

Question 4.) -1 + 3 (x + 2) = ( 1 + 8x)

Please show work if you can

Answer 1

#1. How to solve your question

Your question is

3(2+4)=2(2−2)

3(2x+4)=2(2x-2)3(2x+4)=2(2x−2)

Solve

1

Distribute

3(2+4)=2(2−2)

{\color{#c92786}{3(2x+4)}}=2(2x-2)3(2x+4)=2(2x−2)

6+12=2(2−2)

{\color{#c92786}{6x+12}}=2(2x-2)6x+12=2(2x−2)

2

Distribute

again

6+12=2(2−2)

6x+12={\color{#c92786}{2(2x-2)}}6x+12=2(2x−2)

6+12=4−4

6x+12={\color{#c92786}{4x-4}}6x+12=4x−4

3

Subtract

12

1212

from both sides of the equation

6+12=4−4

6x+12=4x-46x+12=4x−4

6+12−12=4−4−12

6x+12{\color{#c92786}{-12}}=4x-4{\color{#c92786}{-12}}6x+12−12=4x−4−12

4

Simplify

Subtract the numbers

Subtract the numbers

again

6=4−16

6x=4x-166x=4x−16

5

Subtract

4

4x4x

from both sides of the equation

6=4−16

6x=4x-166x=4x−16

6−4=4−16−4

6x{\color{#c92786}{-4x}}=4x-16{\color{#c92786}{-4x}}6x−4x=4x−16−4x

6

Simplify

Combine like terms

Combine like terms

again

2=−16

2x=-162x=−16

7

Divide both sides of the equation by the same term

2=−16

2x=-162x=−16

22=−162

\frac{2x}{{\color{#c92786}{2}}}=\frac{-16}{{\color{#c92786}{2}}}22x=2−16

8

Simplify

Cancel terms that are in both the numerator and denominator