Question

A marble is rolling at a speed of 3.31 m/s  Falls of the end of the table that is 91.2 cm tall.  how long will the marvel be in the air?

Answer 1

d 0.431 seconds

Step-by-step explanation:

`y_0` = Height of the table = 91.2 cm

a = g = Acceleration due to gravity =
`9.81\ \text{m/s}^2`

`u_y` = Initial velocity in y axis = 0

y = Height of floor = 0

t = Time taken to fall to the floor

`y=y_0+u_y+(1)/(2)at^2\\\Rightarrow t=\sqrt{2(y-y_0-u_y)/(a)}\\\Rightarrow t=\sqrt{2* (0-0.912-0)/(-9.81)}\\\Rightarrow t=0.431\ \text{s}`

The marble will be in the air for 0.431 seconds