Question

Factor completely 64y^6-48y^3+9=

Answer 1

To factor completely the expression 64y^6-48y^3+9, we can use the formula for factoring a difference of cubes: a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Step-by-step explanation:

To factor completely the expression 64y^6-48y^3+9, we can use the formula for factoring a difference of cubes: a^3 - b^3 = (a - b)(a^2 + ab + b^2). In this case, a = 4y^2 and b = 3. So we have:

64y^6 - 48y^3 + 9 = (4y^2 - 3)((4y^2)^2 + (4y^2)(3) + (3)^2) = (4y^2 - 3)(16y^4 + 12y^2 + 9).

This expression is now completely factored.

Answer 2

This one is tricky, so I’ll try my best. I believe the answer is: (8y^3-3)^2
I hope that this is helpful, I also included a photo of the answer in case the typed one is difficult to understand.