Question

Gravitational potential energy (Eg) and kinetic energy (Ek)

A 70.0 kg athlete is running at a 12m/s in the 100.0m dash. What is the kinetic energy of the athlete?​

Answer 1

hope it will help you

Step-by-step explanation:

Answer 2

`\boxed {\boxed {\sf E_K= \ 5,040 \ J}}`

Step-by-step explanation:

Kinetic energy is the energy an object possesses due to motion. It is calculated using the following formula:

`E_K= (1)/(2) mv^2`

The mass of the athlete is 70.0 kilograms. The velocity is 12 meters per second.

• m= 70.0 kg
• v= 12 m/s

Substitute the values into the formula.

`E_K= (1)/(2) (70.0 \ kg)(12 \ m/s)^2`

Solve the exponent.

• (12 m/s)² = (12 m/s)(12 m/s) = 144 m²/s²

`E_K= (1)/(2) (70.0 \ kg)(144 \ m^2/s^2)`

Multiply the numbers together.

`E_K= (1)/(2) (10, 080 \ kg*m^2/s^2)`

`E_K= 5,040 \ kg*m^2/s^2`

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer is equal to 5,040 Joules.

`E_K= 5.040 \ J`

The athlete has 5,040 Joules of kinetic energy.