Question

`v^{3)`-
`11v^(2)`+13v-30)÷(v-10)

Answer 1

`v^2-v+3`

Explanation:

`(v^3-11v^2+13v-30)/ (v-10)\\\\(v^3-11v^2+13v-30)/(v-10)\\\\Factorize\:\:v^3-11v^2+13v-30\\\\=(\left(v-10\right)\left(v^2-v+3\right))/(v-10)\\\\\mathrm{Cancel\:the\:common\:factor:}\:v-10\\\\=v^2-v+3`