Question

an object 2cm high when placed in front of a converging mirror produces a virtual image 3cm high. if the object is placed at a distance of 8cm from the pole of the mirror, calculate the position of the image

Answer 1

v= +12cm

Step-by-step explanation:

m = (size of image)/(size of the object) = -v/u

u = - 8 cm

3/2 = -v/u

3/2 = -v/-8

v = +12 cm

Using mirror formula,

1/v + 1/u = 1/f ...(i)

1/12 + 1/(-8) = 1/f

f = -24 cm

Focal length is 24 cm