Question

What are the zeros of y=(x+2)(x-3)^2
And what is the step by step process on how to find it

Answer 1

The zeros are -2 and 3

Explanation:

Set each equation equal to zero

so...

x + 2 = 0

x - 3 = 0

and solve for x

if you don't know how to solve for x...

x + 2 = 0 try to single out x by moving the 2 to the other side

x = -2 the sign changes because it moves to the other side of the equal sign.

There you have it: -2 and 3