Question

Welp pls.i’m so confused

Answer 1

Let's see

• Area=Length×Breadth
• (2x+1)(x-7)=17
• 2x(x-7)+1(x-7)=17
• 2x²-14x+x-7=17
• 2x²-13x-24=0

On solving

• x=8

So

length

• 2(8)+1=17

Width

• 8-7=1

Answer 2

✭ Question -:

A rectangle has a length of (2x+1) units, a width of (x-7) units and an Area of 17 square units. Find the dimensions of the rectangle.

✭ Step-by-step explanation -:

In this question we are provided with the length of a rectangle (2x + 1) units and the width of the rectangle (x - 7). It is also given that the area is 17 units². We are asked to calculate the length and width of the rectangle.

First we will find the value of x

We know,

`\bull \: \small\boxed{ \rm{ Area_((rectangle)) = Length × Width}}`

Substituting the values we get

`\small\sf{ (2x + 1 ) (x - 7) = 17}`

`\small\rm{ 2x( x - 7) + 1(x - 7) = 17}`

`\small\rm{ 2 {x}^(2) - 14x + 1(x - 7) = 17}`

`\small\rm{ 2 {x}^(2) - 13x - 7 = 17}`

`\small\rm{2 {x}^(2) - 13x - 7 - 17 = 0 }`

`\small\rm{2 {x}^(2) - 13x - 24 = 0}`

`\small\rm{x = (13 + 19)/(2 * 2) }`

`\small\rm{ x = (32)/(4) = 8}`

`\small\sf{x = 8}`

Now we will substitute the value of x

Length = (2x + 1) = 2 × 8 + 1 = 16 + 1 = 17 units

Width = (x - 7) = 8 - 7 = 1 units

• Hence, the length of the rectangle is 17 units and the width is 1 units.