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The temperature of a sample of iron with a mass of 10.0 g changed

from 50.4°C to 25.0°C with the release of 114.3 J of heat. What is the
specific heat of iron

User Leo Loki
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1 Answer

3 votes

Answer:

Q = mc(θ₂-θ₁)

47 calories = 10 g *c*(50.4 - 25)

47cal = 10*c* 25.4

47 /(10*25.4) = c

0.185 = c

Specific heat of iron = 0.185 cal/g°C

Step-by-step explanation:

User Sarin Jacob Sunny
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