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A marble rolls down an incline, starting from rest over a distance of 12-centimeters in 1.2-seconds. How fast is it traveling at the bottom of the incline? (Please solve in terms of cm/s and remember that how fast is speed which a positive value.)

User Astr
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Answer:

10 cm/s

Step-by-step explanation:

Given that,

Initial speed of a marble, u = 0

It starts from rest over a distance of 12-centimeters in 1.2-seconds.

We need to find its speed at the bottom of the incline. Let it is v. Speed of an object is equal to distance covered divided by time taken. So,


v=(d)/(t)\\\\v=(12\ cm)/(1.2\ s)\\\\v=10\ cm/s

So, the speed of the marble at the bottom of the incline is 10 cm/s.

User Rego
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