Question

A daring stunt woman sitting on a tree limb

wishes to drop vertically onto a horse gallop-
ing under the tree. The constant speed of the
horse is 6.8 m/s, and the woman is initially
1.91 m above the level of the saddle.
How long is she in the air? The acceleration
of gravity is 9.8 m/s.
Answer in units of s.

Answer 1

she is in the air for approximately 0.62 seconds

Step-by-step explanation:

We want to find the time for a free fall under the acceleration of gravity, covering a distance of 1.91 m, and considering that the woman doesn't impart initial velocity in the vertical direction. So we use the kinematic equation:

`d=v_i\,t+ (g)/(2) \,t^21.91 = 0 +4.9\, t^2\\t^2=1.91/4.9\\t=√(1.91/4.9) \\t\approx 0.624\,\,sec`

Then she is in the air for approximately 0.62 seconds