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A contractor uses a paddle stirrer to mix a can of paint. The paddle turns at 27.6 rad/s and exerts a torque of 16.6 N•m on the paint, doing work on the paint at a rate of Power = 16.6 N•m × 27.6 rad/s = 458.2 W. An internal energy increase of 11.9 kJ causes the temperature of the paint to increase by 1.00K.

If there were no heat flow between the paint and surroundings, what would be the temperature change of the paint as it is stirred for 5.00 mins?​

1 Answer

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P = W/t

t = W/P = 11.9 x 10³ : 458.2 = 25.971 s = 0.433 min

0.433 min = 1 K

so for 5 mins = 0.433 x 5 x 1 K = 2.165 K

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