Answer:
The net force exerted on the race-car driver is 727.3 N
Step-by-step explanation:
Acceleration
According to Newton's second law of motion, the acceleration of an object a is directly proportional to the net force F and inversely proportional to the object's mass m:
![F=m.a](https://img.qammunity.org/2021/formulas/physics/middle-school/x3339d72futztl4dwmvyluz0ql0b4w4383.png)
Since we don't have the value of the acceleration, we must use the kinematic equations to calculate it.
The main formula for accelerated motion is:
![v_f=v_o+a.t](https://img.qammunity.org/2021/formulas/physics/middle-school/wdv6hzhjn14w47hih3u8mwc7otsapd5lba.png)
Where vf is the final speed of the object, vo is its initial speed, a is the acceleration, and t is the time.
The race-car driver accelerates from vo=0 to 50 m/s in t=5.5 s. We can calculate the acceleration, solving the above equation for a:
![\displaystyle a=(v_f-v_o)/(t)](https://img.qammunity.org/2021/formulas/physics/middle-school/gnk7m72pgsvouvn3ei1776clul5czi0j8u.png)
![\displaystyle a=(50-0)/(5.5)](https://img.qammunity.org/2021/formulas/physics/high-school/zh9424wxu80qtm0lttul8gr6r8j5c68rr3.png)
![a=9.09\ m/s^2](https://img.qammunity.org/2021/formulas/physics/high-school/vk1j32dndkir5qyp3j81sjle55wo8uvf5x.png)
Now we calculate the net force:
![F=80\ Kg\cdot 9.09\ m/s^2](https://img.qammunity.org/2021/formulas/physics/high-school/20blgt85xjldriy46pn6s2abmqmkmcu4tf.png)
![\boxed{F=727.3\ N}](https://img.qammunity.org/2021/formulas/physics/high-school/7ccjpo9xenhtve04n5c0uxucsz7fa2wruu.png)
The net force exerted on the race-car driver is 727.3 N