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2. What is the net force exerted on a 80.0 kg race-car driver while the race

car is accelerating from 0 to 50.0 m/s in 5.50 s?*

1 Answer

2 votes

Answer:

The net force exerted on the race-car driver is 727.3 N

Step-by-step explanation:

Acceleration

According to Newton's second law of motion, the acceleration of an object a is directly proportional to the net force F and inversely proportional to the object's mass m:


F=m.a

Since we don't have the value of the acceleration, we must use the kinematic equations to calculate it.

The main formula for accelerated motion is:


v_f=v_o+a.t

Where vf is the final speed of the object, vo is its initial speed, a is the acceleration, and t is the time.

The race-car driver accelerates from vo=0 to 50 m/s in t=5.5 s. We can calculate the acceleration, solving the above equation for a:


\displaystyle a=(v_f-v_o)/(t)


\displaystyle a=(50-0)/(5.5)


a=9.09\ m/s^2

Now we calculate the net force:


F=80\ Kg\cdot 9.09\ m/s^2


\boxed{F=727.3\ N}

The net force exerted on the race-car driver is 727.3 N

User Yagooar
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