Question

What is the value of the expression below when t = 6?

Answer 1

C. -18

I hope that this helped you.

Answer 2

C. -18

Explanation:

The value of the expression is found by substituting the given value for the variable and following the Order of Operations to evaluate it.

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`(2(4(6-t)^2+t-3(t+5)))/(3)\qquad\text{given}\\\\=(2(4(6-6)^2+6-3(6+5)))/(3)=(2(4(0^2)+6-3(11)))/(3)=(2(6-33))/(3)\\\\=(2(-27))/(3)=(-54)/(3)=\boxed{-18}`

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Additional comment

In this instance, the Order of Operations can be shortcut a bit by factoring 3 from the numerator and denominator early in the evaluation.

= 2(2 -11) = 2(-9) = -18