Answer:
Explanation:
The expected value of this distribution will be the Mean
upon calculation
For the distribution of C
1) P(x=xi) 0 1 2 3 4
0 0.20 0.20 0.20 0.20

= 0*0+1*0.2+2*0.2+3*0.2+4*0.2
Mean = 2
2) Standard deviation of C

= 1.09
For the distribution of D
1) P(x=xi) 0 1 2 3 4
0 0.1 0.4 0.2 0.1

= 1.9
2) Standard deviation
= 0.984
Upon comparing the result we observe that
C has greater expected value than D
C has greater standard deviation than D which means it is more spreading of the given data than D.