Answer:
The probability that the lacrosse goalie will make at least 10 saves is 0.558.
Explanation:
Let X denote the number of saves the lacrosse goalie will successfully make.
It is provided that the probability of the lacrosse goalie making a successfully save is, p = 0.80.
It is assumed that all save attempts are independent.
Suppose that the lacrosse goalie attempts to make n = 12 saves.
The random variable X follows a binomial distribution with parameters n = 12 and p = 0.80.
Compute the probability that the lacrosse goalie will make at least 10 saves as follows:
![P(X\geq10 )=P(X=10)+P(X=11)+P(X=12)](https://img.qammunity.org/2021/formulas/mathematics/college/u4xwbo0hyur56cbjvrlsr452ku6ly32sv1.png)
![={12\choose 10}(0.80)^(10)(0.20)^(2)+{12\choose 11}(0.80)^(11)(0.20)^(1)+{12\choose 12}(0.80)^(12)(0.20)^(0)\\\\=0.2835+0.2062+0.0687\\\\=0.5584\\\\\approx 0.558](https://img.qammunity.org/2021/formulas/mathematics/college/rizf2oxaw97uz97loxqhzcunmhitu46c7v.png)
Thus, the probability that the lacrosse goalie will make at least 10 saves is 0.558.