Question

On release 1, a student releases a cart from the top of a ramp, such that the cart travels 190cm before hitting the stopper. The cart increases speed steadily and reaches the bottom of the ramp in 4.00s. What was the magnitude of the cart's acceleration on release 1?

Answer 1

0.2375m/s²

Step-by-step explanation:

Given

S = 190cm = 1.9m

initial velocity u = 0m/s

Time t = 4.00s

Required

acceleration

Using the equation of motion

S = ut + 1/2at²

Substitute

1.9 = 0+1/2a(4)²

1.9 = 8a

a = 1.9/8

a = 0.2375m/s²

The magnitude of the cart's acceleration is 0.2375m/s²