Answer:
the radius of the smaller circle = 3√3.
Explanation:
let C' be the bigger circle
and C be the smaller circle and r its radius.
Area(C') = π × (9² - r²)
Area(C) = π × r²
Area(shaded region) = area(C') - area(C)
= π × (9² - r²)
the statement “the area of the shaded region is twice that of the smaller circle ” means π × (9² - r²) = 2 × π × r²
Now, let’s solve the equation:
π × (9² - r²) = 2 × π × r²
⇔ π × (9² - r² - 2r²) = 0
⇔ π × (81 - 3r²) = 0
⇔ 81 - 3r² = 0
⇔ 81 = 3r²
⇔ r² = 27
⇔ r = √27
⇔ r = 3√3