Question

Two cards are drawn from a deck of 52 playing cards. The first card is NOT replaced into the deck before the 2nd card is drawn. What is the probability of first drawing an Ace, then a Two?

Answer 1

First, we need to keep in mind that there are 52 cards in a deck.
Second, we need the probability of getting an ace.

`(4)/(52\\)` =
`(1)/(13)`
Now that that card is taken out of the deck, we need to subtract that card from the total amount of cards. Now there will be 51 cards.
Next, we need to find the probability of getting a 2. Like the Ace, there 4 of them.
So,

`(4)/(51)`
Now, we multiply both of the probabilities.

`(1)/(13) * (4)/(51) = (4)/(663)`

Since we cannot Reduce, There is your answer!


`(4)/(663)`

∫Maybe·Kuro∫

Answer 2

4/663.

Explanation:

There are 4 aces and 4 2's in a pack of cards.

Prob(First drawing an Ace) = 4/52 = 1/13.

After drawing this card there are now 51 cards left, so:

Prob(Next drawing a 2) = 4/51.

Required probability

= 1/13 * 4/51

= 4/663