Answer:
a) The original length of the garage is 19.13 feet.
b) The new length of the garage is 23.43 feet.
c) Percentage increase in the length of one side is 22.5%.
Explanation:
The original area of the garage = 366
![ft^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/tmw4x6aj8johoay4vo141xymy86g8amzsw.png)
a) Area of a square = length x length (since it has equal length of sides)
=
![l^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tqnintvl21cm0c1vitprbvdzk25j4gabdp.png)
So that;
366 =
![l^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tqnintvl21cm0c1vitprbvdzk25j4gabdp.png)
l =
![√(366)](https://img.qammunity.org/2021/formulas/mathematics/high-school/adiy42sbppxphccrja0y7qrqty4urd8stn.png)
= 19.131
The original length of the garage is 19.13 feet.
b) 50% more force base = 50% x 366
= 0.5 x 366
= 183
The new area of the garage = 366 + 183
= 549
![ft^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/tmw4x6aj8johoay4vo141xymy86g8amzsw.png)
So that;
549 =
![l^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tqnintvl21cm0c1vitprbvdzk25j4gabdp.png)
l =
![√(549)](https://img.qammunity.org/2021/formulas/mathematics/high-school/r8vl8yks5g9m1qllpch3nedlfubwati7ea.png)
= 23.431
The new length of the garage is 23.43 feet.
c) Increase in the length of one side = 23.431 - 19.131
= 4.3 ft
Percentage increase in the length of one side =
x 100%
= 22.48 x 100%
≅ 22.5%
Percentage increase in the length of one side is 22.5%.