Answer:
3886.53
![m^(2)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/jelmjz7kot3sm80pidpl7v5ncxu8balssm.png)
Explanation:
The running track consist of two semicircles and a rectangle.
So that;
Diameter of the semicircles = width of the rectangle = 73 m
radius =
![(diameter)/(2)](https://img.qammunity.org/2021/formulas/physics/middle-school/5hfzzo5jv9oud5snxl1ofegj4tuy30n54z.png)
=
![(73)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/x2ligpe1zxfp69gswp1ak1ocmg6q4n80du.png)
= 36.5 m
But the two semicircles form a circle, so that;
Circumference of a circle = 2
r
Circumference of the circle formed by the semicircles = 2 x
x 36.5
= 229.43 m
Thus,
length of the running track = circumference of the circle formed + length of the two sides of the rectangle
= 229.43 + 84.39 + 84.39
= 398.21 m
The length of the running track is 398.21 m.
Therefore;
Area of the running track = length x width
= 398.21 x 9.76
= 3886.5296
The area of the running track is 3886.53
.