Answer:
6.49m/s
Step-by-step explanation:
Given data
mass of basket ball m1=0.6kg
mass of tennis ball m2= 0.04kg
velocity of basket ball v1=7.2m/s
velocity of tennis ball v2=22m/s
velocity of basket ball v3=?
velocity of tennis ball v4=32.7m/s
we know that the expression for elastic collision is given as
m1v1+m2v2=m1v3+m2v4
substituting we have
0.6*7.2+0.04*22=0.6*x+0.04*32.7
4.32+0.88=0.6x+1.308
solving for x we have
3.892=0.6x
divide both side be 0.6 we have
x=3.892/0.6
x=6.49m/s
The velocity of the basketball after the collision is 6.49m/s