Answer:
1b. 9.51 s
1c. 93.18 m/s.
Step-by-step explanation:
1a. From the question given above, the following data were obtained:
Initial velocity (u) = 0 m/s
Height (h) = 443 m
Acceleration due to gravity (g) = 9.8 m/s²
1b. Determination of the time it takes for the penny to get to the ground.
Height (h) = 443 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
443 = ½ × 9.8 × t²
443 = 4.9 × t²
Divide both side by 4.9
t² = 443/4.9
Take the square root of both side
t = √(443/4.9)
t = 9.51 s
1c. Determination of the speed of the penny before it hits the ground.
Initial velocity (u) = 0 m/s
Height (h) = 443 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) =.?
v² = u² + 2gh
v² = 0² + 2 × 9.8 × 443
v² = 0 + 8682.8
v² = 8682.8
Take the square root of both side
v = √8682.8
v = 93.18 m/s