Answer:
Explanation:
let the number of children be x
and the number of adults be y
so
12x+3y=162-----1
and
8x+3y=122------2
equating both 1 and 2 we have
12x+3y=162-----1
8x+3y=122------2
subtract 2 from 1 we have
12x+3y=162-----1
- 8x+3y=122------2
4y+0=40
4y=40
y=40/4
y=10
put y=4 in eqn 1 we have
12x+3y=162-----1
12x+3*10=162-----1
12x+30=162
12x=162-30
12x=132
x=132/12
x=11
therefore a child will cost $11 and adult will cost $10