Answer:

Explanation:
Let x be a random variable that represent the amount dispensed by a soft-drink dispensing machine which has a normal distribution with mean μ and standard deviation
0.155 ounce.
To find : μ such that P(X>16)=0.01
Consider P(X>16)=0.01

Since,

Also, z-table , one -tailed z-value for p-value of 0.01= 2.326
Then,

