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The "Pick 3" at horse racetracks requires that a person select the winning horse for three consecutive races. If the first race has eleven entries, the second race nine entries, and the third race seven entries, how many different possible tickets might be purchased?

User Llinvokerl
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1 Answer

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Answer:

693

Explanation:

To find the number of possible tickets that would be purchased we simply multiply the total number of choices that each race provides together. This would tell us how many combinations exist which in term is the same as the different possible tickets that can be purchased. Since the choices for the first race are 11, the second race 9, and the third race 7, we multiply these numbers together...

11 * 9 * 7 = 693 possible tickets

User Houdini Sutherland
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